man strmaxcpy () - copy at most a given number of characters of string
NAME
strmaxcpy - copy at most a given number of characters of string
SYNOPSIS
#include <publib.h> char *strmaxcpy(char *tgt, const char *src, size_t n);
DESCRIPTION
strmaxcpy copies up to n-1 characters from the beginning of src to tgt, then adds a '\0'. n must be at least 1. The target string must be large enough to hold the result.
Note that unlike strncpy(3), this function always terminates the result with '\0'. It also doesn't fill the result with extra '\0' characters.
RETURN VALUE
strmaxcpy returns its first argument.
EXAMPLE
To print out the first 69 characters of a string, you might do the following (although familiarity with printf's format string might be more useful in this case).
#include <stdio.h> #include <publib.h>
void print42(const char *string) { char copy[43]; /* 42 + '\0' */
puts(strmaxcpy(copy, string, sizeof(copy))); }
SEE ALSO
AUTHOR
Lars Wirzenius (lars.wirzenius@helsinki.fi)